Solution: Definitons over Venn \( P(A\given B) = \frac{y}{y + z}\) \( P(A\given \neg B) = \frac{x}{x+t} \) \( P(A\cap \neg B) = \frac{x}{x+y+z+t}\) \( P(B\given A\cap B) = 1 \) \( P(A\cup B) = \frac{x+y+z}{x+y+z+t} \) Back to exercise